A mega geeky awk one-liner today. Tested on Solaris under bash, so YMMV.

Have you ever found that a filesystem is filling up fast, and dont know what is causing it? This one liner (which can be placed in a cron job if you like) is best run as a super user.

It will:

1. Search for all files in the current dir and subdirs that are modified in the last 3 days;
2. list them, filtering just the filesize and name/path;
3. sort/order by the largest file; and
4. Email you a copy of the report.

 find / -type f -mtime -3 -exec ls -l {} \; 2>/dev/null \
 | awk '{print $5 " " $9}' \
 | awk '{printf "%12d\t%s\n", $1, substr($0,index($0,$2),80)}' \
 | sort -r >/tmp/largefiles.txt && \
 ( uuencode /tmp/largefiles.txt largefiles.txt ) \
 | mailx -s 'Large Files Report' -r mail2@youremail.com `cat /tmp/mailrecipients` &
 
Nice. If you just want to see the response on stdout then try this:
 
 find / -type f -mtime -3 -exec ls -l {} \; 2>/dev/null \
 | awk '{print $5 " " $9}' \
 | awk '{printf "%12d\t%s\n", $1, substr($0,index($0,$2),80)}' \
 | sort -r
 
Have fun.